{"id":159,"date":"2020-09-21T12:17:09","date_gmt":"2020-09-21T07:17:09","guid":{"rendered":"https:\/\/talib.pk\/test-preparation\/?p=159"},"modified":"2020-09-21T12:17:09","modified_gmt":"2020-09-21T07:17:09","slug":"1st-year-chemistry-thermochemistry-mcqs-with-answers","status":"publish","type":"post","link":"https:\/\/talib.pk\/test-preparation\/1st-year-chemistry-thermochemistry-mcqs-with-answers\/","title":{"rendered":"1st Year Chemistry Thermochemistry MCQs with Answers"},"content":{"rendered":"<div class=\"28d95f43054b69d67289d6316e9506d8\" data-index=\"1\" style=\"float: none; margin:12px 0 12px 0; text-align:center;\">\n<script async src=\"\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\r\n<!-- talib-new -->\r\n<ins class=\"adsbygoogle\"\r\n     style=\"display:block\"\r\n     data-ad-client=\"ca-pub-3438155045791616\"\r\n     data-ad-slot=\"6774242552\"\r\n     data-ad-format=\"auto\"><\/ins>\r\n<script>\r\n(adsbygoogle = window.adsbygoogle || []).push({});\r\n<\/script>\n<\/div>\n<p>Here you will get the 1st Year Chemistry Thermochemistry MCQs with Answers. In Chemical Reactions, there are reactions in which heat is evolved or involved. In a chemical reaction, there are spontaneous and non-spontaneous reactions. There are three things in a chemical reaction, System, Surrounding, and State Function. The First Law of Thermodynamics is very valuable. Enthalpy is also a crucial term for Chemical Reactions. Enthalpy can be measured in two ways i.e. Glass Calorimeter and Bomb Calorimeter. Hess&#8217;s Law plays an important role in Reactions. The Born-Haber cycle is an important application of Hess&#8217;s Law. So, get the important MCQs of Thermochemistry on this page given below.<\/p>\n<h2 style=\"text-align: center;\">1st Year Chemistry Thermochemistry MCQs with Answers<\/h2>\n<p><img decoding=\"async\" loading=\"lazy\" class=\"size-full wp-image-594 aligncenter\" src=\"https:\/\/talib.pk\/test-preparation\/wp-content\/uploads\/2020\/09\/Chemistry-8.jpg\" alt=\"1st Year Chemistry Thermochemistry MCQs with Answers\" width=\"300\" height=\"300\" srcset=\"https:\/\/talib.pk\/test-preparation\/wp-content\/uploads\/2020\/09\/Chemistry-8.jpg 300w, https:\/\/talib.pk\/test-preparation\/wp-content\/uploads\/2020\/09\/Chemistry-8-150x150.jpg 150w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<h3><strong>KEY POINTS<\/strong><\/h3>\n<div class=\"box info  alignleft\" style=\"width:100%\"><div class=\"box-inner-block\"><i class=\"fa tie-shortcode-boxicon\"><\/i>\n\t\t\t\n<div class=\"lightbulb tie-list-shortcode\">\n<ul>\n<li>Spontaneous and non-spontaneous reaction<\/li>\n<li>System, Surrounding and State Function<\/li>\n<li>Internal Energy<\/li>\n<li>1st law of Thermodynamics<\/li>\n<li>Enthalpy of a reaction<\/li>\n<li>Measurement of Enthalpy<\/li>\n<li>Hess&#8217;s Law<\/li>\n<li>Born-Haber Cycle<\/li>\n<\/ul>\n<\/div>\n\t\t\t<\/div><\/div>\n<p>&nbsp;<\/p>\n<p><strong><span style=\"color: #ff6600;\">Question#1<\/span>. Enthalpy of neutralization of strong acids and strong bases have the same values because:<\/strong><\/p>\n<ul>\n<li>Neutralization leads to the formation of salt and water<\/li>\n<li>Strong acids and bases are ionic substances<\/li>\n<li>Acids always give rise to H<sup>+<\/sup> and bases always furnish OH<sup>-1<\/sup> ions<\/li>\n<li>The net change involves the combination of H<sup>+<\/sup> and OH<sup>-1 <\/sup>ions form water<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>The net change involves the combination of H<sup>+<\/sup> and OH<sup>-1 <\/sup>ions form water<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#2<\/span>. For an endothermic reaction, enthalpy of reactants:<\/strong><\/p>\n<ul>\n<li>Is smaller than that of the products<\/li>\n<li>Is greater than that of the products<\/li>\n<li>Is equal to that of the products<\/li>\n<li>Must be greater or smaller than that of the products<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Is smaller than that of the products<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#3<\/span>. Which of the following has a positive value of enthalpy:<\/strong><\/p>\n<ul>\n<li>Neutralization<\/li>\n<li>Atomization<strong><br \/>\n<\/strong><\/li>\n<li>Combustion<\/li>\n<li>All of the above<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Atomization<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#4<\/span>. The net heat change in the chemical reaction is the same whether it is brought about in two or more different ways in one or several steps. It is known as:<\/strong><\/p>\n<ul>\n<li>Henry\u2019s law<\/li>\n<li>Hess\u2019s law<\/li>\n<li>Joule\u2019s principal<\/li>\n<li>Law of conservation of energy<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Hess\u2019s law<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#5<\/span>. Hess\u2019s law is analogous to:<\/strong><\/p>\n<ul>\n<li>Law of heat summation<\/li>\n<li>Law of increasing entropy<\/li>\n<li>Law of heat exchange<\/li>\n<li>1<sup>st<\/sup> law of thermodynamics<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Law of heat summation<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#6<\/span>. NaOH + HCl\u00a0\u00a0 \u2192\u00a0\u00a0 NaCl + H<sub>2<\/sub>O<\/strong><br \/>\n<strong>Enthalpy change in the above reaction is called:<\/strong><\/p>\n<ul>\n<li>Enthalpy of reaction<\/li>\n<li>Enthalpy of neutralization<\/li>\n<li>Enthalpy of formation<\/li>\n<li>Enthalpy of combustion<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Enthalpy of neutralization<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#7<\/span>. A hypothetical reaction X \u2192 2Yproceeds by the following sequence of steps:<\/strong><br \/>\n<strong>1\/2X \u2192 Z\u00a0\u00a0 \u2206H = q<sub>1<\/sub><\/strong><br \/>\n<strong>Z \u2192 2W\u00a0\u00a0\u00a0\u00a0 \u2206H = q<sub>2<\/sub><\/strong><br \/>\n<strong>W \u2192 1\/2Y\u00a0\u00a0 \u2206H = q<sub>3<\/sub><\/strong><br \/>\n<strong>The values for the \u2206H of the reaction is:<\/strong><\/p>\n<ul>\n<li>q<sub>1<\/sub> + q<sub>2<\/sub> + q<sub>3<\/sub><\/li>\n<li>2(q<sub>1<\/sub> + q<sub>2<\/sub> + q<sub>3<\/sub>)<\/li>\n<li>2q<sub>1<\/sub> + 2q<sub>2<\/sub> + 3q<sub>3<\/sub><\/li>\n<li>2(q<sub>1<\/sub> + q<sub>2<\/sub> + q<sub>3<\/sub>)<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>2(q<sub>1<\/sub> + q<sub>2<\/sub> + q<sub>3<\/sub>)<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#8<\/span>. Calories are equivalent to:<\/strong><\/p>\n<ul>\n<li>0.4184 J<\/li>\n<li>40.18 J<\/li>\n<li>4.184 J<\/li>\n<li>418.4 J<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>4.184 J<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#9<\/span>. The values of \u2206H for the process I<sub>(g)<\/sub> + e<sup>-1<\/sup>\u00a0 \u2192 I<sup>-1<\/sup><sub>(g)<\/sub> is:<\/strong><\/p>\n<ul>\n<li>&gt; 0<\/li>\n<li>0<\/li>\n<li>&lt; 0<\/li>\n<li>None of the above<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>&lt; 0<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#10<\/span>. The enthalpy of formation of a compound is:<\/strong><\/p>\n<ul>\n<li>Positive<\/li>\n<li>Either positive or negative<\/li>\n<li>Negative<\/li>\n<li>None of the above<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Either positive or negative<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#11<\/span>. What is correct about the heat of combustion:<\/strong><\/p>\n<ul>\n<li>It is positive in some cases while negative in other<\/li>\n<li>It is applicable to gaseous substances only<\/li>\n<li>It is always negative<\/li>\n<li>It is always positive<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>It is always negative<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#12<\/span>. What is not correct about \u2206H<sub>f<\/sub>?<\/strong><\/p>\n<ul>\n<li>Its value gives an idea about the relative stability of reactants and the products<\/li>\n<li>It is always negative<\/li>\n<li>Values depend upon the nature of bonds<\/li>\n<li>Its value can be greater or less than zero<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>It is always negative<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#13<\/span>. If an endothermic reaction is allowed to take place very rapidly in air, the temperature of the surrounding air will?<\/strong><\/p>\n<ul>\n<li>Remains constant<\/li>\n<li>Decrease<strong><br \/>\n<\/strong><\/li>\n<li>Increase<\/li>\n<li>Either increase or decrease<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Decrease<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#14<\/span>. When a solid melts, there is:<\/strong><\/p>\n<ul>\n<li>Increase in entropy<\/li>\n<li>The decrease in internal energy<\/li>\n<li>Increase in enthalpy<\/li>\n<li>Both a and b<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Both a and b<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#15<\/span>. The heat of reaction depends upon:<\/strong><\/p>\n<ul>\n<li>The temperature of the reactants<\/li>\n<li>Physical states of the reactants and the products<\/li>\n<li>Both a and b<\/li>\n<li>Path of the reaction and the temperature<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Both a and b<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#16<\/span>. The exothermic process is:<\/strong><\/p>\n<ul>\n<li>Evaporation<\/li>\n<li>Respiration<\/li>\n<li>Sublimation<\/li>\n<li>Boiling<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Respiration<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#17<\/span>. During an exothermic or endothermic reaction which one of the following formulae is used to calculate the amount of heat evolved or absorbed_____.<\/strong><\/p>\n<ul>\n<li>\u2206H = \u2206E + PV<\/li>\n<li>\u2206p = \u2206H<\/li>\n<li>\u2206E = q + w<\/li>\n<li>q = m x s x \u2206T<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>q = m x s x \u2206T<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#18<\/span>. Most of the reactions which give stable products are:<\/strong><\/p>\n<ul>\n<li>Endothermic<\/li>\n<li>Isothermal<\/li>\n<li>Exothermic<\/li>\n<li>None of these<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Exothermic<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#19<\/span>. The measurement of enthalpy change at standard conditions means that we should manage the measurement that______.<\/strong><\/p>\n<ul>\n<li>24\u00b0C at 1 atm<\/li>\n<li>0\u00b0C at 1 atm<\/li>\n<li>25\u00b0C at 1 atm<\/li>\n<li>100\u00b0C 1 at atm<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>0\u00b0C at 1 atm<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#20<\/span>. The total heat content of a system is called_______.<\/strong><\/p>\n<ul>\n<li>Internal energy<\/li>\n<li>Enthalpy<\/li>\n<li>Entropy<\/li>\n<li>All of these<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Enthalpy<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#21<\/span>. The enthalpies of all elements in their standard states are:<\/strong><\/p>\n<ul>\n<li>Unity<\/li>\n<li>Always +ve<\/li>\n<li>Always \u2013ve<\/li>\n<li>Zero<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Zero<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#22<\/span>. A state function which describes together the internal energy and product of pressure and volume is called_______.<\/strong><\/p>\n<ul>\n<li>Enthalpy<\/li>\n<li>Internal energy<\/li>\n<li>Work<\/li>\n<li>Kinetic energy<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Enthalpy<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#23<\/span>. The enthalpy change for the reaction C<sub>2<\/sub>H<sub>2<\/sub> + 5\/2 O<sub>2<\/sub> \u2192 2CO<sub>2<\/sub> + H<sub>2<\/sub>O is brown as enthalpy of:<\/strong><\/p>\n<ul>\n<li>Formation of CO<sub>2<\/sub><\/li>\n<li>Combustion of C<sub>2<\/sub>H<sub>2<\/sub><\/li>\n<li>Fusion of C<sub>2<\/sub>H<sub>2<\/sub><\/li>\n<li>Vaporization of C<sub>2<\/sub>H<sub>2<\/sub><\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Combustion of C<sub>2<\/sub>H<sub>2<\/sub><\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#24<\/span>. The value of \u2206V is very small. The term P\u2206V can be neglected for the process involving:<\/strong><\/p>\n<ul>\n<li>Liquid and gas<\/li>\n<li>Liquid and solid<\/li>\n<li>Solid and gases<\/li>\n<li>None of these<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Liquid and solid<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#25<\/span>. The lattice energy of NaCl is:<\/strong><\/p>\n<ul>\n<li>787 J\/mole<\/li>\n<li>780 kJ\/mol<\/li>\n<li>790 kJ\/mol<\/li>\n<li>-787 kJ\/mole<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>-787 kJ\/mole<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#26<\/span>. Decomposition of H<sub>2<\/sub>O is:<\/strong><\/p>\n<ul>\n<li>Endothermic reaction<\/li>\n<li>Exothermic reaction<\/li>\n<li>Nuclear reaction<\/li>\n<li>Zero nuclear reaction<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Endothermic reaction<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#27<\/span>. According to Hess\u2019s Law, the enthalpy change for a reaction:<\/strong><\/p>\n<ul>\n<li>Depends on path<\/li>\n<li>The sum of \u2206E and \u2206H<\/li>\n<li>Independent of the path<\/li>\n<li>None of these<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Independent of the path<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#28<\/span>. Enthalpy of formation of one mole of an ionic compound from gaseous ion under standard condition is called______.<\/strong><\/p>\n<ul>\n<li>Gibb\u2019s energy<\/li>\n<li>Lattice energy<\/li>\n<li>Bond energy<\/li>\n<li>All of these<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>Lattice energy<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#29<\/span>. Choose from the following the correct statement about Born Harbor cycle:<\/strong><\/p>\n<ul>\n<li>Born Harbor cycle is different from Hess\u2019s law<\/li>\n<li>The energy changes in a cyclic process is not zero<\/li>\n<li>The lattice energy of crystalline substances can be calculated easily<\/li>\n<li>None of these<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>The lattice energy of crystalline substances can be calculated easily<\/strong>\n\t\t\t<\/div><\/div>\n<p><strong><span style=\"color: #ff6600;\">Question#30<\/span>. Change in enthalpy of \u2206H a system can be calculated by the following relationship:<\/strong><\/p>\n<ul>\n<li>\u2206H = \u2206E-PV<\/li>\n<li>\u2206H = \u2206E-Q<\/li>\n<li>\u2206H = \u2206E+q<\/li>\n<li>\u2206H = \u2206E+P\u2206V<\/li>\n<\/ul>\n<div class=\"clear\"><\/div><div class=\"toggle close\"><h3 class=\"toggle-head-open\">Answer<i class=\"fa fa-angle-up\"><\/i><\/h3><h3 class=\"toggle-head-close\">Answer<i class=\"fa fa-angle-down\"><\/i><\/h3><div class=\"toggle-content\">\n\t\t\t<strong>\u2206H = \u2206E+P\u2206V<\/strong>\n\t\t\t<\/div><\/div>\n\n<div style=\"font-size: 0px; height: 0px; line-height: 0px; margin: 0; padding: 0; clear: both;\"><\/div>","protected":false},"excerpt":{"rendered":"<p>Here you will get the 1st Year Chemistry Thermochemistry MCQs with Answers. In Chemical Reactions, there are reactions in which heat is evolved or involved. In a chemical reaction, there are spontaneous and non-spontaneous reactions. There are three things in a chemical reaction, System, Surrounding, and State Function. The First Law of Thermodynamics is very &hellip;<\/p>\n","protected":false},"author":2,"featured_media":594,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":[],"categories":[4],"tags":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/posts\/159"}],"collection":[{"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/comments?post=159"}],"version-history":[{"count":0,"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/posts\/159\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/media\/594"}],"wp:attachment":[{"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/media?parent=159"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/categories?post=159"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/talib.pk\/test-preparation\/wp-json\/wp\/v2\/tags?post=159"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}